EASA NAV(A)intermediate
54. Distance 210 NM, TAS 130 kt, headwind 15 kt, ETD 0915 UTC. What is ETA?
Answer
1105 UTC
Explanation
Groundspeed is $130−15=115$ kt. Time is $210/115≈1.83$ h, about 1 h 50 min; added to 0915 gives approximately **1105 UTC**. **Key takeaway:** Use groundspeed—not TAS—for ETA. **Glossary:** GS: groundspeed; ETD: estimated time of departure.
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