EASA NAV(A)intermediate
An aircraft flies at TAS 180 kt with a 25 kt headwind for 2 h 25 min. How far does it travel over the ground?
Answer
375 NM
Explanation
Approximate GS = 180 − 25 = 155 kt. The time is 2 + 25/60 = 2.417 h; distance = 155 × 2.417 ≈ **375 NM**. **Key takeaway:** Ground distance is groundspeed multiplied by time. **Glossary:** Headwind: wind component opposing the direction of travel.
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