EASA NAV(A)intermediate
Given TC 283°, distance 75 NM, TAS 105 kt, and a 12 kt headwind, with ETD 1242 UTC, what is ETA?
Answer
1330 UTC
Explanation
Approximate GS is 105 − 12 = 93 kt. The leg takes 75/93 hours, about 48 minutes. Adding 48 minutes to 1242 gives **1330 UTC**. **Key takeaway:** ETA equals departure time plus distance divided by groundspeed. **Glossary:** GS: speed relative to the ground.
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