EASA NAV(A)advanced
GS 160 kt, TC 177°, wind 140°/20 kt. What is the approximate TH?
Answer
173°
Explanation
The wind from 140° has a crosswind component from the left of the near-southerly course, requiring a small leftward angular correction according to the keyed vector solution. The resulting TH is approximately 173°. **Key takeaway:** Solve wind direction as a vector relative to the desired track, not by comparing wind and course numbers alone. **Glossary:** **Wind vector**: Direction and speed of wind; **crosswind**: Wind component perpendicular to track.
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