EASA NAV(A)advanced
Given WCA −012°, TH 125°, MC 139°, and DEV 002°E, find TC, MH, and CH.
Answer
TC 137°, MH 127°, CH 125°
Explanation
Using the question's sign convention, TC = TH − WCA = 125° − (−12°) = 137°. MH is 127° from the 12° true-to-magnetic difference implied by the supplied values, and CH = MH − 2° east deviation = 125°. **Key takeaway:** Work through true, magnetic, and compass references in order and preserve stated signs. **Glossary:** **TC**: True course; **TH**: True heading; **MH**: Magnetic heading; **CH**: Compass heading; **WCA**: Wind correction angle.
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