Social Media Management intermediate
A 0.01 M solution of fully ionized HCl has what pH, assuming ideal dilute behavior?
Answer
2
Explanation
Because HCl is treated as a strong acid, it is completely ionized, so $[H^+]=0.01=10^{-2}$ M. Therefore $pH=-\log_{10}(10^{-2})=2$. **Key takeaway:** For a fully ionized strong monoprotic acid, hydrogen ion concentration equals acid concentration. **Glossary:** Strong acid: acid that ionizes nearly completely in water.
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