An aircraft has flown 60 nautical miles (NM) and is 6 NM right of its planned track. The destination is 60 NM ahead. What total heading correction is required to regain the track at the destination?

### Why this is right The aircraft is right of track, so it must turn left to close the displacement. Its track error is 6 degrees, and the equal remaining distance produces a 6-degree closing angle, for a total correction of 12 degrees left. ### The concept The 1-in-60 rule estimates small navigation angles: each nautical mile of displacement over 60 nautical miles corresponds to about 1 degree. Use distance already flown for track error and distance remaining for closing angle. Add the two angles when the aim is to regain track at the destination. ### The other options - **6 degrees left**: this corrects only the track error and ignores the angle needed to close on the destination. - **6 degrees right**: this turns farther away from the planned track. - **12 degrees right**: the magnitude is correct, but the direction is wrong. ### Worked numbers - **Given**: displacement 6 NM; flown distance 60 NM; remaining distance 60 NM. - **Find**: total correction in degrees. - **Formula**: angle = displacement / distance × 60. - **Solve**: track error = 6 / 60 × 60 = 6 degrees. Closing angle = 6 / 60 × 60 = 6 degrees. Total = 6 + 6 = 12 degrees. - **Answer**: 12 degrees left. - **Check**: both angles act toward the track, so the aircraft must turn left. ### Terms - **NM**: Nautical mile, a unit of distance used in aviation. - **Track error angle**: The estimated angle between the intended track and the aircraft's present ground track. - **Closing angle**: The angle needed to reach the planned track at a selected point. ### Remember Use flown distance for track error and remaining distance for closing angle.