An aircraft has TAS 180 kt and a 25 kt headwind. How far does it travel over the ground in 2 hours 25 minutes, assuming the wind is aligned with the route?
Answer
375 NM
Explanation
The groundspeed is $180-25=155$ kt. The time is 2 hours 25 minutes, or $2.4167$ hours. Distance is $155\times2.4167\approx374.6$ NM, which rounds to 375 NM. The headwind reduces forward groundspeed.\n\n**Key takeaway:** Find GS first, then multiply by elapsed time.\n\n**Glossary:** **TAS**: true airspeed; **headwind**: wind component opposing the direction of travel.